{"id":1325,"date":"2024-09-23T14:59:12","date_gmt":"2024-09-23T12:59:12","guid":{"rendered":"https:\/\/solveredu.com\/?p=1325"},"modified":"2026-01-27T23:48:56","modified_gmt":"2026-01-27T22:48:56","slug":"beams-with-hinges-example-solutions","status":"publish","type":"post","link":"https:\/\/solveredu.com\/tr\/post\/obliczanie-belek-z-przegubem\/","title":{"rendered":"Mente\u015feli Kiri\u015flerin Hesaplanmas\u0131"},"content":{"rendered":"

Bu giri\u015fte:<\/p>\n\n\n\n

    \n
  1. Mafsall\u0131 bir kiri\u015f i\u00e7in \u00e7\u00f6z\u00fcm \u00f6rne\u011fi.<\/a><\/li>\n\n\n\n
  2. \u00c7ok a\u00e7\u0131kl\u0131kl\u0131 bir kiri\u015f i\u00e7in \u00e7\u00f6z\u00fcm \u00f6rne\u011fi.<\/a><\/li>\n<\/ol>\n\n\n\n

    Mafsall\u0131 Kiri\u015flerin Hesaplanmas\u0131 - G\u00f6rev \u00f6rnekleri<\/h1>\n\n\n\n

    A\u015fa\u011f\u0131daki \u015fekilde \u00e7\u00f6zece\u011fimiz bir kiri\u015f g\u00f6receksiniz. Kiri\u015fte bir tane var i\u00e7 eklem<\/strong>.<\/p>\n\n\n\n

    \"Reaksiyonlar<\/figure>\n\n\n\n

    Kiri\u015flerin hesaplanmas\u0131na, kiri\u015f i\u00e7in statik belirlenebilirli\u011fi kontrol ederek ba\u015flar\u0131z. Statik belirlenebilirlik kontrol\u00fc hakk\u0131nda daha fazla bilgi i\u00e7in bkz. Burada<\/a>.<\/p>\n\n\n\n

    N=R-J-3<\/em>=4-1-3=0
    Nerede?
    N - statik derecesi sonu\u00e7suz
    R =4 - destek reaksiyonlar\u0131n\u0131n say\u0131s\u0131
    J =1 - i\u00e7 ba\u011flant\u0131lar\u0131n say\u0131s\u0131
    3 - denge denklemlerinin say\u0131s\u0131. Statik sistemlerde bu say\u0131 3't\u00fcr<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Statik belirlenebilirlik derecesinin belirlenmesinde B noktas\u0131nda bir i\u00e7 mafsal oldu\u011fu i\u00e7in J yerine 1 koyar\u0131z. Elde etti\u011fimiz sonu\u00e7 s\u0131f\u0131rd\u0131r, dolay\u0131s\u0131yla kiri\u015f statik olarak belirlenebilirdir. Bir sonraki ad\u0131mda denge denklemlerinden reaksiyonlar\u0131 hesaplayaca\u011f\u0131z.<\/p>\n\n\n\n

    Kiri\u015f diyagram\u0131, t\u00fcm hesaplamalar ve i\u00e7 kuvvet diyagramlar\u0131 benim Belek Hesaplama<\/a>. \u00c7evrimi\u00e7i olarak kiri\u015f diyagramlar\u0131 olu\u015fturabilir ve her bir statik olarak belirlenmi\u015f kiri\u015f i\u00e7in ayr\u0131nt\u0131l\u0131 bir \u00e7\u00f6z\u00fcm elde edebilirsiniz. <\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Tepkileri d\u00fcz bir kiri\u015f i\u00e7in oldu\u011fu gibi hesaplar\u0131z. Mente\u015fe nedeniyle, ek bir denge denklemi yaz\u0131yoruz.<\/p>\n\n\n\n

    \"Reaksiyonlar<\/figure>\n\n\n\n

    Sa\u011f taraftaki B noktas\u0131 ile ilgili momentlerin toplam\u0131 s\u0131f\u0131rd\u0131r. Mente\u015fe, e\u011filme momenti denklemini kiri\u015fin sa\u011f ya da sol kenarlar\u0131ndan yaln\u0131zca biri i\u00e7in yazmam\u0131za olanak tan\u0131r. Se\u00e7im bize kalm\u0131\u015ft\u0131r. Bu \u00f6rnekte, sa\u011f taraf\u0131n se\u00e7ilmesi tercih edilir.<\/p>\n\n\n\n

    \u015eimdi reaksiyonlar hesapland\u0131\u011f\u0131na g\u00f6re, a\u015fa\u011f\u0131daki de\u011ferlerin belirlenmesine ge\u00e7elim i\u00e7 kuvvetler<\/a> b\u00f6lmelerde.<\/p>\n\n\n\n

    Mafsall\u0131 bir kiri\u015fte, d\u00fcz bir kiri\u015fte oldu\u011fu gibi ayn\u0131 \u015fekilde ilerleriz. Tart\u0131\u015f\u0131lan \u00f6rnekte \u00fc\u00e7 b\u00f6lmemiz bulunmaktad\u0131r. Kesme kuvvetlerinin ve e\u011filme momentlerinin belirlenmesini a\u015fa\u011f\u0131daki \u015fekilde bulacaks\u0131n\u0131z.<\/p>\n\n\n\n

    \"Normal<\/figure>\n\n\n\n
    \"Normal<\/figure>\n\n\n\n
    \"Normal<\/figure>\n\n\n\n
    B noktas\u0131ndaki ba\u011flant\u0131da e\u011filme momentinin s\u0131f\u0131r oldu\u011funa dikkat edin. Bunun nedeni, bir mafsal\u0131n tan\u0131m\u0131 gere\u011fi bir e\u011filme momenti iletmemesidir, bu nedenle mafsalda s\u0131f\u0131r e\u011filme momenti her zaman mafsall\u0131 bir kiri\u015f ile yap\u0131lan i\u015flerde ortaya \u00e7\u0131kmal\u0131d\u0131r.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Karakteristik noktalardaki kesme kuvvetleri ve e\u011filme momentleri belirlendikten sonra, diyagramlar\u0131 \u00e7izmeye ge\u00e7ebiliriz.<\/p>\n\n\n\n

    \"Normal<\/figure>\n\n\n\n

    Bu da bir i\u00e7 mafsall\u0131 kiri\u015f \u00f6rne\u011finin \u00e7\u00f6z\u00fcm\u00fcn\u00fc tamamlamaktad\u0131r.<\/p>\n\n\n\n

    \u00c7ok a\u00e7\u0131kl\u0131kl\u0131 bir kiri\u015f i\u00e7in \u00e7\u00f6z\u00fcm \u00f6rne\u011fi<\/h2>\n\n\n\n

    Ba\u015fka bir \u00f6rnek olarak, iki mente\u015feli bir kiri\u015fi \u00e7\u00f6zece\u011fiz. Prosed\u00fcr, tek mente\u015feli kiri\u015f i\u00e7in olanla ayn\u0131d\u0131r. Aradaki fark denge denklemlerini yazarken ortaya \u00e7\u0131kacakt\u0131r. Bu durumda bir denklemimiz daha olacakt\u0131r.<\/p>\n\n\n\n

    \"Multibeam,<\/figure>\n\n\n\n

    B\u00f6yle bir kiri\u015f i\u00e7in statik belirlenebilirlik kontrol\u00fc a\u015fa\u011f\u0131daki gibidir.<\/p>\n\n\n\n

    N=R-J-3<\/em>=5-2-3=0
    Nerede?
    N - statik derecesi sonu\u00e7suz
    R =5 - destek reaksiyonlar\u0131n\u0131n say\u0131s\u0131
    J =2 - i\u00e7 ba\u011flant\u0131lar\u0131n say\u0131s\u0131
    3 - denge denklemlerinin say\u0131s\u0131. Statik sistemlerde bu say\u0131 3't\u00fcr<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Statik belirlenebilirlik derecesini belirlerken B ve D noktalar\u0131nda bir i\u00e7 mente\u015feye sahip oldu\u011fumuzdan, J yerine \"2\" koyar\u0131z. Elde etti\u011fimiz sonu\u00e7 s\u0131f\u0131rd\u0131r, yani kiri\u015f statik olarak belirlenebilirdir. Bir sonraki ad\u0131mda denge denklemlerinden reaksiyonlar\u0131 hesaplayaca\u011f\u0131z.<\/p>\n\n\n\n

    \"Reaksiyonlar<\/figure>\n\n\n\n

    Tepkileri d\u00fcz bir kiri\u015f i\u00e7in oldu\u011fu gibi hesaplar\u0131z. Mente\u015feler nedeniyle, iki ek denge denklemi yaz\u0131yoruz.<\/p>\n\n\n\n

    T\u0131pk\u0131 tek mafsall\u0131 bir kiri\u015fte oldu\u011fu gibi, mafsaldaki e\u011filme momentini belirleyece\u011fimiz taraf\u0131 se\u00e7ebiliriz. Bu \u00f6rnekte, sol taraf tercih edilir. Hem B mente\u015fesi hem de D noktas\u0131ndaki mente\u015fe i\u00e7in.<\/p>\n\n\n\n

    \u015eimdi reaksiyonlar hesapland\u0131\u011f\u0131na g\u00f6re, a\u015fa\u011f\u0131daki de\u011ferlerin belirlenmesine ge\u00e7elim i\u00e7 kuvvetler<\/a> b\u00f6lmelerde.<\/p>\n\n\n\n

    Mafsall\u0131 bir kiri\u015fte, d\u00fcz bir kiri\u015fte oldu\u011fu gibi hareket ederiz. Bu \u00f6rnekte, alt\u0131 kadar b\u00f6lmemiz var. Kesme kuvvetlerini ve e\u011filme momentlerini a\u015fa\u011f\u0131daki \u015fekilde bulabilirsiniz.<\/p>\n\n\n\n

    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    B noktas\u0131ndaki mafsalda ve D mafsal\u0131nda e\u011filme momentinin s\u0131f\u0131r oldu\u011funa dikkat edin. Bunun nedeni, bir mafsal\u0131n tan\u0131m\u0131 gere\u011fi bir e\u011filme momenti iletmemesidir, bu nedenle mafsall\u0131 kiri\u015f g\u00f6revlerinde her zaman mafsalda s\u0131f\u0131r bir e\u011filme momenti ortaya \u00e7\u0131kmal\u0131d\u0131r.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Son olarak, kesme kuvvetleri ve e\u011filme momentlerinin seyrini diyagramlar \u015feklinde belirleyece\u011fiz.<\/p>\n\n\n\n

    \"Mente\u015feli<\/figure>\n\n\n\n

    \"Mafsall\u0131 kiri\u015flerin hesaplanmas\u0131\" yaz\u0131s\u0131n\u0131n sonuna geldik. Sonuna kadar geldi\u011finiz i\u00e7in te\u015fekk\u00fcr ederiz.<\/p>","protected":false},"excerpt":{"rendered":"

    W tym wpisie: Obliczanie Belek z przegubem – Przyk\u0142adowe rozwi\u0105zania zada\u0144 Poni\u017cej na rys. Znajdziesz belk\u0119 kt\u00f3ra rozwi\u0105\u017cemy. Belka posiada jeden przegub wewn\u0119trzny. Obliczanie belek rozpoczynamy od sprawdzenia statycznej wyznaczalno\u015bci dla belki wygl\u0105da nast\u0119puj\u0105co. Wi\u0119cej o sprawdzeniu statycznej wyznaczalno\u015bci znajdziesz tutaj. N=R-J-3=4-1-3=0gdzie:N \u2013 stopie\u0144 statycznej niewyznaczalno\u015b\u0107R =4 \u2013 liczba reakcji podporowychJ =1 \u2013 liczba przegub\u00f3w […]<\/p>\n","protected":false},"author":255930052,"featured_media":1355,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_wpcom_ai_launchpad_first_post":false,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"jetpack_post_was_ever_published":false},"categories":[14815,14816],"tags":[14855,14857,14856,14859,14858],"class_list":["post-1325","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mechanika","category-wytrzymalosc-materialow","tag-belka-z-przegubem","tag-momenty-gnace","tag-przegub-wewnetrzny","tag-wykres-sil-tnacych","tag-wykresy-momentu-gnacego"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2024\/09\/wykresy_2-1.png?fit=1033%2C886&ssl=1","jetpack_shortlink":"https:\/\/wp.me\/pg3flK-ln","jetpack-related-posts":[],"jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/posts\/1325","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/users\/255930052"}],"replies":[{"embeddable":true,"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/comments?post=1325"}],"version-history":[{"count":24,"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/posts\/1325\/revisions"}],"predecessor-version":[{"id":3079,"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/posts\/1325\/revisions\/3079"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/media\/1355"}],"wp:attachment":[{"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/media?parent=1325"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/categories?post=1325"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/solveredu.com\/tr\/wp-json\/wp\/v2\/tags?post=1325"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}