{"id":3128,"date":"2026-03-06T14:33:37","date_gmt":"2026-03-06T13:33:37","guid":{"rendered":"https:\/\/solveredu.com\/?p=3128"},"modified":"2026-03-06T14:33:42","modified_gmt":"2026-03-06T13:33:42","slug":"calcolo-deflessione-trave","status":"publish","type":"post","link":"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/","title":{"rendered":"Calcolo della deflessione delle travi: Dall'integrazione del momento flettente a un calcolatore online"},"content":{"rendered":"<p class=\"has-text-align-left wp-block-paragraph\" id=\"foo\">La determinazione della linea di deflessione \u00e8 uno dei passaggi chiave della progettazione strutturale. Che siate studenti che si preparano a un colloquio sulla resistenza dei materiali o ingegneri che verificano la rigidit\u00e0 di un componente, dovete sapere come \u201efunziona\u201d la trave sotto carico.<\/p>\n\n\n\n<p class=\"has-text-align-left wp-block-paragraph\">In questo articolo, percorreremo l'intero percorso: dalla teoria classica <strong>l'integrazione dell'equazione differenziale della linea di deflessione<\/strong>, attraverso il disegno pratico dei diagrammi degli angoli di rotazione, con esempi per <strong>una trave semplicemente appoggiata<\/strong> e <strong>staffa<\/strong><\/p>\n\n\n\n<p class=\"has-text-align-left wp-block-paragraph\" id=\"foo\">E se tenete conto del vostro tempo e volete evitare noiosi calcoli a mano, alla fine dell'articolo troverete il mio <strong>calcolatore del fascio proprietario<\/strong>, che eseguir\u00e0 queste operazioni per voi in pochi secondi. Cominciamo!<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong><a href=\"#Teoria-i-Metodyka\" data-type=\"internal\" data-id=\"#Teoria-i-Metodyka\">Base teorica: Equazione differenziale della linea di deflessione<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#calkowanie\">Metodo analitico: integrazione passo-passo<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Przyk\u0142ad1\">Esempio 1: Trave semplicemente appoggiata<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Przyk\u0142ad2\">Esempio 2: Trave a sbalzo<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Sprawd\u017a\">Verifica rapida: utilizzare il calcolatore di travi online<\/a><\/strong><\/li>\n<\/ol>\n\n\n\n<h2 id=\"Teoria-i-Metodyka\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">1. Teoria e metodologia: da dove viene la deviazione?<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Calcolo della deflessione della trave<\/strong> \u00e8 uno degli elementi pi\u00f9 importanti per la verifica dello Stato Limite di Servizio (SGU). Per comprendere questo processo, \u00e8 necessario tornare alle fondamenta della <strong>equazione differenziale della linea di deflessione del fascio<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">La relazione fondamentale che lega <strong>momento flettente vs. deflessione<\/strong>, \u00e8 descritto dalla formula:<\/p>\n\n\n\n<div class=\"wp-block-math has-medium-font-size\"><math display=\"block\"><semantics><mrow><mi>E<\/mi><mi>I<\/mi><mo>\u22c5<\/mo><msup><mi>y<\/mi><mrow><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><\/mrow><\/msup><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><mo>=<\/mo><mo form=\"prefix\" stretchy=\"false\">\u2212<\/mo><mi>M<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">EI \u0192cdot y\u201d(x) = -M(x)<\/annotation><\/semantics><\/math><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Dove:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><math data-latex=\"EI \"><semantics><mrow><mi>E<\/mi><mi>I<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">EI <\/annotation><\/semantics><\/math>- che <strong>rigidit\u00e0 flessionale della trave<\/strong> (E - modulo di Young, I - momento d'inerzia della sezione).<\/li>\n\n\n\n<li><math data-latex=\"y''(x)\"><semantics><mrow><msup><mi>y<\/mi><mrow><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><\/mrow><\/msup><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">y\u201d(x)<\/annotation><\/semantics><\/math> - \u00e8 la derivata seconda della deflessione (curvatura).<\/li>\n\n\n\n<li><math data-latex=\"M(x)\"><semantics><mrow><mi>M<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">M(x)<\/annotation><\/semantics><\/math> - \u00e8 una funzione del momento flettente in una determinata sezione.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">La nostra applicazione <strong>metodo analitico per il calcolo delle deflessioni<\/strong> \u00e8 quello di scalare due volte questa equazione, passando dalle forze interne alla deformazione effettiva del componente.<\/p>\n\n\n\n<h2 id=\"calkowanie\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">2. integrare passo dopo passo l'equazione della retta di deflessione<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Questa parte del calcolo della deflessione della trave \u00e8 in genere la pi\u00f9 problematica a causa degli integrali, che non piacciono a tutti. Nel caso delle equazioni del momento per le travi, si tratta in genere di funzioni semplici da integrare, quindi non c'\u00e8 da preoccuparsi. <strong>Integrazione dell'equazione della linea di deflessione<\/strong> si svolge in due fasi:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li><strong>Prima integrazione:<\/strong> Permette di ricavare la funzione degli angoli di rotazione delle sezioni trasversali <math data-latex=\"\\theta(x)\"><semantics><mrow><mi>\u03b8<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">\\\u00b4theta(x)<\/annotation><\/semantics><\/math><\/li>\n\n\n\n<li><strong>Seconda integrazione:<\/strong> Consente di determinare la funzione di deflessione <math data-latex=\"y(x)\"><semantics><mrow><mi>y<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">y(x)<\/annotation><\/semantics><\/math>, che \u00e8 la linea di deflessione ricercata.<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">Durante il calcolo compaiono le costanti di integrazione C1 e C2. Per determinarle, \u00e8 necessario definire le cosiddette \"costanti di integrazione\". <strong>condizioni iniziali<\/strong>, risultante dal modo in cui la trave \u00e8 sostenuta (ad esempio, nessuna deflessione in corrispondenza dell'appoggio).<\/p>\n\n\n\n<h2 id=\"Przyk\u0142ad1\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">3 Esempio 1: trave semplicemente appoggiata - deflessione e calcoli<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Questo \u00e8 il caso pi\u00f9 comune nel settore delle costruzioni. <strong>Trave semplicemente appoggiata e sua deflessione<\/strong> con un carico concentrato o uniforme \u00e8 un classico dei compiti d'esame.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Di seguito troverete un esempio di soluzione per il calcolo della deflessione di una trave. Per le soluzioni di esempio ho utilizzato <a href=\"https:\/\/solveredu.com\/it\/calcolatore-di-travi\/\" data-type=\"page\" data-id=\"166\">calcolatore di raggi<\/a> che vi raccomando.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Nel nostro esempio, c'\u00e8 una trave di 2 m di lunghezza appoggiata a due estremit\u00e0 e caricata con un carico continuo q e una forza concentrata F. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"724\" height=\"668\" data-attachment-id=\"3143\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/1-5\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?fit=724%2C668&amp;ssl=1\" data-orig-size=\"724,668\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"1\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?fit=724%2C668&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=724%2C668&#038;ssl=1\" alt=\"una trave lunga 2 m sostenuta alle due estremit\u00e0 e caricata con un carico continuo q e una forza concentrata F, solveredu\" class=\"wp-image-3143\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?w=724&amp;ssl=1 724w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=300%2C277&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=13%2C12&amp;ssl=1 13w\" sizes=\"auto, (max-width: 724px) 100vw, 724px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Per calcolare la deflessione, abbiamo bisogno del momento flettente, quindi prima dobbiamo risolvere la trave determinando le equazioni della reazione e del momento flettente. Per saperne di pi\u00f9, consultare questo documento <a href=\"https:\/\/solveredu.com\/it\/post\/forze-interne-nelle-travi\/\" data-type=\"post\" data-id=\"899\">ingresso<\/a>. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Calcolo delle reazioni nei supporti. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"556\" height=\"273\" data-attachment-id=\"3144\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-5\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?fit=556%2C273&amp;ssl=1\" data-orig-size=\"556,273\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?fit=556%2C273&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=556%2C273&#038;ssl=1\" alt=\"\" class=\"wp-image-3144\" style=\"aspect-ratio:2.036689370957587;width:406px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?w=556&amp;ssl=1 556w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=300%2C147&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=18%2C9&amp;ssl=1 18w\" sizes=\"auto, (max-width: 556px) 100vw, 556px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Calcolo del momento flettente nei compartimenti. <\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"520\" data-attachment-id=\"3145\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/3-4\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?fit=1114%2C566&amp;ssl=1\" data-orig-size=\"1114,566\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?fit=1024%2C520&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=1024%2C520&#038;ssl=1\" alt=\"\" class=\"wp-image-3145\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=1024%2C520&amp;ssl=1 1024w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=300%2C152&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=768%2C390&amp;ssl=1 768w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=18%2C9&amp;ssl=1 18w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?w=1114&amp;ssl=1 1114w\" sizes=\"auto, (max-width: 1000px) 100vw, 1000px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una volta determinate le equazioni del momento flettente per la nostra trave di esempio, possiamo passare all'integrazione e alla determinazione della linea di deflessione. Per fare ci\u00f2, utilizziamo le equazioni del momento flettente per ogni comparto calcolate nel passaggio precedente e le integriamo due volte. La prima equazione ci d\u00e0 la soluzione per l'angolo di deviazione, la seconda per la deflessione. Si ottengono cos\u00ec 4 costanti di integrazione C1, C2, C3, C4. due costanti per ogni compartimento. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"718\" height=\"259\" data-attachment-id=\"3147\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/4-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?fit=718%2C259&amp;ssl=1\" data-orig-size=\"718,259\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"4\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?fit=718%2C259&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=718%2C259&#038;ssl=1\" alt=\"calcolo della deflessione della trave, risolto\" class=\"wp-image-3147\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?w=718&amp;ssl=1 718w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=300%2C108&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=18%2C6&amp;ssl=1 18w\" sizes=\"auto, (max-width: 718px) 100vw, 718px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Nella fase successiva, dobbiamo calcolare le costanti di integrazione. A tale scopo utilizzeremo le condizioni iniziali.<strong> Il principio \u00e8 che abbiamo bisogno di tante condizioni quante sono le costanti di integrazione<\/strong>- Nel nostro caso 4. In corrispondenza degli appoggi siamo sicuri che non ci sar\u00e0 alcuna deflessione della trave, quindi y(x) in corrispondenza degli appoggi viene assunta uguale a zero. Inoltre, sappiamo che alla giunzione dei due compartimenti dobbiamo avere continuit\u00e0 della deflessione e dell'angolo di deflessione, quindi abbiamo due equazioni aggiuntive.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"522\" height=\"193\" data-attachment-id=\"3149\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/5-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?fit=522%2C193&amp;ssl=1\" data-orig-size=\"522,193\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"5\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?fit=522%2C193&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=522%2C193&#038;ssl=1\" alt=\"\" class=\"wp-image-3149\" style=\"aspect-ratio:2.7048012306695814;width:439px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?w=522&amp;ssl=1 522w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=300%2C111&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=18%2C7&amp;ssl=1 18w\" sizes=\"auto, (max-width: 522px) 100vw, 522px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una volta stabilite le condizioni al contorno, si procede a calcolare le costanti di integrazione sostituendo i valori appropriati nelle equazioni. Si tratta ora di pura matematica. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">I risultati ottenuti per le costanti di integrazione<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"477\" height=\"82\" data-attachment-id=\"3151\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/6-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?fit=477%2C82&amp;ssl=1\" data-orig-size=\"477,82\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"6\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?fit=477%2C82&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=477%2C82&#038;ssl=1\" alt=\"\" class=\"wp-image-3151\" style=\"aspect-ratio:5.817991233085572;width:414px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?w=477&amp;ssl=1 477w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=300%2C52&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=18%2C3&amp;ssl=1 18w\" sizes=\"auto, (max-width: 477px) 100vw, 477px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Dopo aver sostituito le costanti di integrazione nelle equazioni, si ottiene la forma finale delle equazioni:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"752\" height=\"237\" data-attachment-id=\"3153\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/attachment\/7\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?fit=752%2C237&amp;ssl=1\" data-orig-size=\"752,237\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"7\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?fit=752%2C237&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=752%2C237&#038;ssl=1\" alt=\"\" class=\"wp-image-3153\" style=\"aspect-ratio:3.1733845169545747;width:606px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?w=752&amp;ssl=1 752w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=300%2C95&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=18%2C6&amp;ssl=1 18w\" sizes=\"auto, (max-width: 752px) 100vw, 752px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una volta ottenute le equazioni in questa forma, sostituendo i numeri compresi tra 0 e 2 m al posto di x si otterranno la freccia di deflessione e l'angolo di deflessione della trave lungo la sua lunghezza, che possono essere tracciati in un grafico. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"759\" height=\"737\" data-attachment-id=\"3155\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/attachment\/8\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?fit=759%2C737&amp;ssl=1\" data-orig-size=\"759,737\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?fit=759%2C737&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=759%2C737&#038;ssl=1\" alt=\"flessione e angolo di deflessione di un esempio di trave semplicemente appoggiata, risolta\" class=\"wp-image-3155\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?w=759&amp;ssl=1 759w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=300%2C291&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=12%2C12&amp;ssl=1 12w\" sizes=\"auto, (max-width: 759px) 100vw, 759px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<h2 id=\"Przyk\u0142ad2\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">Esempio 2: Trave a sbalzo - deflessione e calcoli<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Nel caso di <strong>staffa, calcolo della deflessione<\/strong> hanno un aspetto leggermente diverso a causa del contenimento. W <strong>trave a sbalzo<\/strong> la massima deflessione e il massimo angolo di rotazione si verificano all'estremit\u00e0 libera stessa.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Di seguito troverete un esempio di soluzione per il calcolo della deflessione di una trave. Per le soluzioni di esempio ho utilizzato <a href=\"https:\/\/solveredu.com\/it\/calcolatore-di-travi\/\" data-type=\"page\" data-id=\"166\">calcolatore di raggi<\/a> che vi raccomando.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Nel nostro esempio, c'\u00e8 una trave di lunghezza L vincolata all'estremit\u00e0 sinistra nel punto A e caricata con una forza concentrata F=5qL all'altra estremit\u00e0.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"695\" height=\"666\" data-attachment-id=\"3158\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-1\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?fit=695%2C666&amp;ssl=1\" data-orig-size=\"695,666\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.1\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?fit=695%2C666&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=695%2C666&#038;ssl=1\" alt=\"lunghezza della trave a sbalzo L, momento flettente , solveredu\" class=\"wp-image-3158\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?w=695&amp;ssl=1 695w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=300%2C287&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=13%2C12&amp;ssl=1 13w\" sizes=\"auto, (max-width: 695px) 100vw, 695px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Per calcolare la deflessione, abbiamo bisogno del momento flettente, quindi prima dobbiamo risolvere la trave determinando le equazioni della reazione e del momento flettente. Per saperne di pi\u00f9, consultare questo documento <a href=\"https:\/\/solveredu.com\/it\/post\/forze-interne-nelle-travi\/\" data-type=\"post\" data-id=\"899\">ingresso<\/a>. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Calcolo delle reazioni nei supporti. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"366\" height=\"270\" data-attachment-id=\"3160\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-3-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?fit=366%2C270&amp;ssl=1\" data-orig-size=\"366,270\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?fit=366%2C270&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=366%2C270&#038;ssl=1\" alt=\"\" class=\"wp-image-3160\" style=\"aspect-ratio:1.3556545896515801;width:283px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?w=366&amp;ssl=1 366w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=300%2C221&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=16%2C12&amp;ssl=1 16w\" sizes=\"auto, (max-width: 366px) 100vw, 366px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Calcolo del momento flettente nei compartimenti. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"466\" height=\"263\" data-attachment-id=\"3161\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-4-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?fit=466%2C263&amp;ssl=1\" data-orig-size=\"466,263\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.4\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?fit=466%2C263&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=466%2C263&#038;ssl=1\" alt=\"\" class=\"wp-image-3161\" style=\"aspect-ratio:1.7719089774820271;width:346px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?w=466&amp;ssl=1 466w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=300%2C169&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=18%2C10&amp;ssl=1 18w\" sizes=\"auto, (max-width: 466px) 100vw, 466px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una volta determinate le equazioni del momento flettente per la nostra trave di esempio, possiamo passare all'integrazione e alla determinazione della linea di deflessione. A tale scopo utilizziamo l'equazione del momento flettente e la integriamo due volte. La prima equazione ci d\u00e0 la soluzione per l'angolo di flessione, la seconda per la deflessione. Otteniamo cos\u00ec le 2 costanti di integrazione C1 e C2.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"594\" height=\"165\" data-attachment-id=\"3162\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-5-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?fit=594%2C165&amp;ssl=1\" data-orig-size=\"594,165\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.5\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?fit=594%2C165&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=594%2C165&#038;ssl=1\" alt=\"\" class=\"wp-image-3162\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?w=594&amp;ssl=1 594w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=300%2C83&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=18%2C5&amp;ssl=1 18w\" sizes=\"auto, (max-width: 594px) 100vw, 594px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Nella fase successiva, dobbiamo calcolare le costanti di integrazione. Per questo schema \u00e8 fondamentale che nel punto di vincolo sia la deflessione che l'angolo di rotazione siano nulli. Con questo <strong>diagramma degli angoli di rotazione e deflessione<\/strong> parte da valori nulli in corrispondenza della parete e aumenta rapidamente verso l'estremit\u00e0 della trave.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"536\" height=\"227\" data-attachment-id=\"3163\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-6\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?fit=536%2C227&amp;ssl=1\" data-orig-size=\"536,227\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.6\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?fit=536%2C227&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=536%2C227&#038;ssl=1\" alt=\"\" class=\"wp-image-3163\" style=\"aspect-ratio:2.361489742530635;width:505px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?w=536&amp;ssl=1 536w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=300%2C127&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=18%2C8&amp;ssl=1 18w\" sizes=\"auto, (max-width: 536px) 100vw, 536px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Dopo aver sostituito le costanti di integrazione nelle equazioni, si ottiene la forma finale delle equazioni:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"582\" height=\"136\" data-attachment-id=\"3165\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-7\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?fit=582%2C136&amp;ssl=1\" data-orig-size=\"582,136\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.7\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?fit=582%2C136&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=582%2C136&#038;ssl=1\" alt=\"\" class=\"wp-image-3165\" style=\"aspect-ratio:4.279551337359793;width:533px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?w=582&amp;ssl=1 582w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=300%2C70&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=18%2C4&amp;ssl=1 18w\" sizes=\"auto, (max-width: 582px) 100vw, 582px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una volta ottenute le equazioni in questa forma, sostituendo i numeri da 0 a L al posto di x si otterr\u00e0 la freccia di deflessione e l'angolo di deflessione della trave lungo la sua lunghezza e si potr\u00e0 tracciare un grafico.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"641\" height=\"618\" data-attachment-id=\"3166\" data-permalink=\"https:\/\/solveredu.com\/it\/post\/obliczanie-ugiecia-belki\/2-2-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&amp;ssl=1\" data-orig-size=\"641,618\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=641%2C618&#038;ssl=1\" alt=\"\" class=\"wp-image-3166\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?w=641&amp;ssl=1 641w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=300%2C289&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=12%2C12&amp;ssl=1 12w\" sizes=\"auto, (max-width: 641px) 100vw, 641px\" \/><\/figure>\n\n\n\n<h2 id=\"Sprawd\u017a\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">5 Controllare i risultati: Calcolo online delle travi<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">L'integrazione manuale del momento flettente \u00e8 una delle abilit\u00e0 pi\u00f9 importanti nello studio della resistenza dei materiali. \u00c8 cos\u00ec che si inizia a capire come funziona una trave. Il problema \u00e8 che nei compiti pi\u00f9 complessi \u00e8 molto facile commettere un piccolo errore: un segno del momento, una condizione al contorno scritta male o un errore nell'integrazione.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Per questo motivo ho creato un calcolatore della deflessione delle travi che consente di <strong>verificare i calcoli<\/strong> - soprattutto con gli esempi pi\u00f9 difficili.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Questo strumento pu\u00f2 aiutarvi:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Controllare i risultati<\/strong><br>Confrontate la soluzione calcolata manualmente con il risultato del modello computazionale e assicuratevi che gli integrali e le condizioni al contorno siano corretti.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Comprendere meglio il comportamento della trave<\/strong><br>I grafici generati automaticamente delle forze di taglio, dei momenti flettenti e delle linee di deflessione aiutano a capire cosa sta realmente accadendo nella struttura.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Affrontare i compiti pi\u00f9 difficili<\/strong><br>Il supporto per diversi schemi di carico e di supporto rende lo strumento ideale per gli esempi pi\u00f9 impegnativi di compiti o progetti.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Se volete essere sicuri che i vostri calcoli siano corretti - <strong>controllarli in pochi secondi.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-buttons is-content-justification-center is-layout-flex wp-container-core-buttons-is-layout-69bbf988 wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-text-align-center wp-element-button\" href=\"https:\/\/solveredu.com\/it\/calcolatore-di-travi\/\" style=\"border-top-left-radius:8px;border-top-right-radius:8px;border-bottom-left-radius:8px;border-bottom-right-radius:8px\">Prova gratis<\/a><\/div>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Non lasciate che un piccolo errore di integrazione rovini l'intero compito. Verificate i vostri calcoli e imparate la resistenza dei materiali molto pi\u00f9 velocemente.<\/p>","protected":false},"excerpt":{"rendered":"<p>Wyznaczanie linii ugi\u0119cia to jeden z kluczowych etap\u00f3w projektowania konstrukcji. Niezale\u017cnie od tego, czy jeste\u015b studentem przygotowuj\u0105cym si\u0119 do kolokwium z wytrzyma\u0142o\u015bci materia\u0142\u00f3w, czy in\u017cynierem weryfikuj\u0105cym sztywno\u015b\u0107 elementu, musisz wiedzie\u0107, jak \u201epracuje\u201d belka pod obci\u0105\u017ceniem. W tym artykule przejdziemy pe\u0142n\u0105 \u015bcie\u017ck\u0119: od klasycznej teorii ca\u0142kowania r\u00f3wnania r\u00f3\u017cniczkowego linii ugi\u0119cia, przez praktyczne rysowanie wykres\u00f3w k\u0105t\u00f3w obrotu, [&hellip;]<\/p>\n","protected":false},"author":255930052,"featured_media":3166,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_wpcom_ai_launchpad_first_post":false,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"jetpack_post_was_ever_published":false},"categories":[14815,14816],"tags":[14846,14820,14845,14847],"class_list":["post-3128","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mechanika","category-wytrzymalosc-materialow","tag-belka-swobodnie-podparta","tag-rownania-rownowagi","tag-reakcje-podporowe","tag-stateczna-wyznaczalnosc"],"jetpack_publicize_connections":[],"jetpack_shortlink":"https:\/\/wp.me\/pg3flK-Os","jetpack-related-posts":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&ssl=1","_links":{"self":[{"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/posts\/3128","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/users\/255930052"}],"replies":[{"embeddable":true,"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/comments?post=3128"}],"version-history":[{"count":31,"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/posts\/3128\/revisions"}],"predecessor-version":[{"id":3175,"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/posts\/3128\/revisions\/3175"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/media\/3166"}],"wp:attachment":[{"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/media?parent=3128"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/categories?post=3128"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/solveredu.com\/it\/wp-json\/wp\/v2\/tags?post=3128"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}