{"id":3128,"date":"2026-03-06T14:33:37","date_gmt":"2026-03-06T13:33:37","guid":{"rendered":"https:\/\/solveredu.com\/?p=3128"},"modified":"2026-03-06T14:33:42","modified_gmt":"2026-03-06T13:33:42","slug":"calculo-deflexion-vigas","status":"publish","type":"post","link":"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/","title":{"rendered":"C\u00e1lculo de la deflexi\u00f3n de vigas: Desde la integraci\u00f3n del momento flector hasta una calculadora online"},"content":{"rendered":"<p class=\"has-text-align-left wp-block-paragraph\" id=\"foo\">Determinar la l\u00ednea de deflexi\u00f3n es uno de los pasos clave en el dise\u00f1o estructural. Tanto si eres un estudiante que se prepara para un coloquio sobre resistencia de materiales como un ingeniero que verifica la rigidez de un componente, necesitas saber c\u00f3mo \u201efunciona\u201d la viga bajo carga.<\/p>\n\n\n\n<p class=\"has-text-align-left wp-block-paragraph\">En este art\u00edculo, recorreremos el camino completo: desde la teor\u00eda cl\u00e1sica <strong>integraci\u00f3n de la ecuaci\u00f3n diferencial de la l\u00ednea de desviaci\u00f3n<\/strong>, mediante el dibujo pr\u00e1ctico de diagramas de \u00e1ngulos de rotaci\u00f3n a ejemplos para <strong>una viga simplemente apoyada<\/strong> y <strong>soporte<\/strong><\/p>\n\n\n\n<p class=\"has-text-align-left wp-block-paragraph\" id=\"foo\">Y si valoras tu tiempo y quieres evitar tediosos c\u00e1lculos manuales, al final del art\u00edculo encontrar\u00e1s mi <strong>calculadora de haces propia<\/strong>, que realizar\u00e1 estas operaciones por ti en cuesti\u00f3n de segundos. Empecemos.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong><a href=\"#Teoria-i-Metodyka\" data-type=\"internal\" data-id=\"#Teoria-i-Metodyka\">Base te\u00f3rica: Ecuaci\u00f3n diferencial de la l\u00ednea de desviaci\u00f3n.<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#calkowanie\">M\u00e9todo anal\u00edtico: integraci\u00f3n paso a paso<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Przyk\u0142ad1\">Ejemplo 1: Viga simplemente apoyada<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Przyk\u0142ad2\">Ejemplo 2: Viga en voladizo<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Sprawd\u017a\">Verificaci\u00f3n r\u00e1pida: utilice la calculadora de vigas en l\u00ednea<\/a><\/strong><\/li>\n<\/ol>\n\n\n\n<h2 id=\"Teoria-i-Metodyka\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">1. Teor\u00eda y metodolog\u00eda: \u00bfde d\u00f3nde procede la desviaci\u00f3n?<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>C\u00e1lculo de la deformaci\u00f3n de la viga<\/strong> es uno de los elementos m\u00e1s importantes de la comprobaci\u00f3n del Estado L\u00edmite de Servicio (ELS). Para entender este proceso, hay que remontarse a los fundamentos de la <strong>ecuaci\u00f3n diferencial de la l\u00ednea de desviaci\u00f3n de la viga<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">La relaci\u00f3n fundamental que une <strong>momento flector vs. deflexi\u00f3n<\/strong>, se describe mediante la f\u00f3rmula:<\/p>\n\n\n\n<div class=\"wp-block-math has-medium-font-size\"><math display=\"block\"><semantics><mrow><mi>E<\/mi><mi>I<\/mi><mo>\u22c5<\/mo><msup><mi>y<\/mi><mrow><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><\/mrow><\/msup><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><mo>=<\/mo><mo form=\"prefix\" stretchy=\"false\">\u2212<\/mo><mi>M<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">EI \u0192cdot y\u201d(x) = -M(x)<\/annotation><\/semantics><\/math><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">D\u00f3nde:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><math data-latex=\"EI \"><semantics><mrow><mi>E<\/mi><mi>I<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">EI <\/annotation><\/semantics><\/math>- que <strong>rigidez a la flexi\u00f3n de la viga<\/strong> (E - m\u00f3dulo de Young, I - momento de inercia de la secci\u00f3n).<\/li>\n\n\n\n<li><math data-latex=\"y''(x)\"><semantics><mrow><msup><mi>y<\/mi><mrow><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><\/mrow><\/msup><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">y\u201d(x)<\/annotation><\/semantics><\/math> - es la segunda derivada de la desviaci\u00f3n (curvatura).<\/li>\n\n\n\n<li><math data-latex=\"M(x)\"><semantics><mrow><mi>M<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">M(x)<\/annotation><\/semantics><\/math> - es funci\u00f3n del momento flector en una secci\u00f3n determinada.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Nuestra aplicaci\u00f3n <strong>m\u00e9todo anal\u00edtico para el c\u00e1lculo de las deformaciones<\/strong> es escalar dos veces esta ecuaci\u00f3n, pasando de las fuerzas internas a la deformaci\u00f3n real del componente.<\/p>\n\n\n\n<h2 id=\"calkowanie\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">2. integrar paso a paso la ecuaci\u00f3n de la l\u00ednea de desviaci\u00f3n<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Esta parte del c\u00e1lculo de la flecha de la viga suele ser la que causa m\u00e1s problemas debido a las integrales, que no gustan a todo el mundo. En el caso de las ecuaciones de momento para vigas, suelen ser funciones sencillas de integrar, por lo que no hay de qu\u00e9 preocuparse. <strong>Integraci\u00f3n de la ecuaci\u00f3n de la l\u00ednea de desviaci\u00f3n<\/strong> se lleva a cabo en dos etapas:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li><strong>Primera integraci\u00f3n:<\/strong> Permite obtener la funci\u00f3n de los \u00e1ngulos de rotaci\u00f3n de las secciones transversales <math data-latex=\"\\theta(x)\"><semantics><mrow><mi>\u03b8<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">\\theta(x)<\/annotation><\/semantics><\/math><\/li>\n\n\n\n<li><strong>Segunda integraci\u00f3n:<\/strong> Permite determinar la funci\u00f3n de deformaci\u00f3n <math data-latex=\"y(x)\"><semantics><mrow><mi>y<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">y(x)<\/annotation><\/semantics><\/math>, que es la l\u00ednea de desviaci\u00f3n buscada.<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">Durante el c\u00e1lculo, aparecen las constantes de integraci\u00f3n C1 y C2. Para determinarlas, necesitamos definir las llamadas \"constantes de integraci\u00f3n\". <strong>condiciones iniciales<\/strong>, resultante de la forma en que est\u00e1 apoyada la viga (por ejemplo, sin flexi\u00f3n en el apoyo).<\/p>\n\n\n\n<h2 id=\"Przyk\u0142ad1\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">3 Ejemplo 1: Viga simplemente apoyada - flexi\u00f3n y c\u00e1lculos<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Este es el caso m\u00e1s com\u00fan en el sector de la construcci\u00f3n. <strong>Viga simplemente apoyada y su deformaci\u00f3n<\/strong> con una carga concentrada o uniforme es un cl\u00e1sico de las tareas de examen.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A continuaci\u00f3n encontrar\u00e1s un ejemplo de soluci\u00f3n para calcular la flexi\u00f3n de una viga. Para las soluciones de ejemplo he utilizado <a href=\"https:\/\/solveredu.com\/es\/calculadora-de-vigas\/\" data-type=\"page\" data-id=\"166\">calculadora de haces<\/a> que te recomiendo.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">En nuestro ejemplo, hay una viga de 2 m de longitud apoyada en dos extremos y cargada con una carga continua q y una fuerza concentrada F. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"724\" height=\"668\" data-attachment-id=\"3143\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/1-5\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?fit=724%2C668&amp;ssl=1\" data-orig-size=\"724,668\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"1\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?fit=724%2C668&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=724%2C668&#038;ssl=1\" alt=\"una viga de 2 m de longitud apoyada en ambos extremos y cargada con una carga continua q y una fuerza concentrada F, solveredu\" class=\"wp-image-3143\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?w=724&amp;ssl=1 724w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=300%2C277&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=13%2C12&amp;ssl=1 13w\" sizes=\"auto, (max-width: 724px) 100vw, 724px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Para calcular la flexi\u00f3n, necesitaremos el momento flector, as\u00ed que primero tenemos que resolver la viga determinando las ecuaciones de reacci\u00f3n y momento flector. M\u00e1s informaci\u00f3n en <a href=\"https:\/\/solveredu.com\/es\/post\/fuerzas-internas-en-vigas\/\" data-type=\"post\" data-id=\"899\">entrada<\/a>. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C\u00e1lculo de reacciones en soportes. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"556\" height=\"273\" data-attachment-id=\"3144\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-5\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?fit=556%2C273&amp;ssl=1\" data-orig-size=\"556,273\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?fit=556%2C273&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=556%2C273&#038;ssl=1\" alt=\"\" class=\"wp-image-3144\" style=\"aspect-ratio:2.036689370957587;width:406px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?w=556&amp;ssl=1 556w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=300%2C147&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=18%2C9&amp;ssl=1 18w\" sizes=\"auto, (max-width: 556px) 100vw, 556px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">C\u00e1lculo del momento flector en compartimentos. <\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"520\" data-attachment-id=\"3145\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/3-4\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?fit=1114%2C566&amp;ssl=1\" data-orig-size=\"1114,566\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?fit=1024%2C520&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=1024%2C520&#038;ssl=1\" alt=\"\" class=\"wp-image-3145\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=1024%2C520&amp;ssl=1 1024w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=300%2C152&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=768%2C390&amp;ssl=1 768w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=18%2C9&amp;ssl=1 18w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?w=1114&amp;ssl=1 1114w\" sizes=\"auto, (max-width: 1000px) 100vw, 1000px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una vez determinadas las ecuaciones del momento flector de nuestra viga de ejemplo, podemos pasar a la integraci\u00f3n y a la determinaci\u00f3n de la l\u00ednea de flexi\u00f3n. Para ello, utilizamos las ecuaciones del momento flector de cada compartimento calculadas en el paso anterior y las integramos dos veces. La primera ecuaci\u00f3n nos da la soluci\u00f3n para el \u00e1ngulo de flexi\u00f3n y la segunda para la deformaci\u00f3n. Y as\u00ed obtenemos 4 constantes de integraci\u00f3n C1, C2, C3, C4. dos constantes para cada compartimento. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"718\" height=\"259\" data-attachment-id=\"3147\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/4-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?fit=718%2C259&amp;ssl=1\" data-orig-size=\"718,259\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"4\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?fit=718%2C259&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=718%2C259&#038;ssl=1\" alt=\"c\u00e1lculo de la desviaci\u00f3n de la viga, solvered\" class=\"wp-image-3147\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?w=718&amp;ssl=1 718w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=300%2C108&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=18%2C6&amp;ssl=1 18w\" sizes=\"auto, (max-width: 718px) 100vw, 718px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">En el siguiente paso, tenemos que calcular las constantes de integraci\u00f3n. Para ello utilizaremos las condiciones iniciales.<strong> El principio es que necesitamos tantas condiciones como constantes de integraci\u00f3n haya<\/strong>- En nuestro caso 4. En los lugares de los apoyos estamos seguros de que no habr\u00e1 deflexi\u00f3n de la viga por lo que y(x) en los lugares de los apoyos se toma igual a cero. Adem\u00e1s, sabemos que en la uni\u00f3n de los dos compartimentos debemos tener continuidad de deflexi\u00f3n y \u00e1ngulo de deflexi\u00f3n, por lo que tenemos dos ecuaciones adicionales.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"522\" height=\"193\" data-attachment-id=\"3149\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/5-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?fit=522%2C193&amp;ssl=1\" data-orig-size=\"522,193\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"5\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?fit=522%2C193&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=522%2C193&#038;ssl=1\" alt=\"\" class=\"wp-image-3149\" style=\"aspect-ratio:2.7048012306695814;width:439px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?w=522&amp;ssl=1 522w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=300%2C111&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=18%2C7&amp;ssl=1 18w\" sizes=\"auto, (max-width: 522px) 100vw, 522px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una vez establecidas las condiciones de contorno, procedemos a calcular las constantes de integraci\u00f3n sustituyendo los valores adecuados en las ecuaciones. Esto ya es pura matem\u00e1tica. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Los resultados obtenidos para las constantes de integraci\u00f3n<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"477\" height=\"82\" data-attachment-id=\"3151\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/6-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?fit=477%2C82&amp;ssl=1\" data-orig-size=\"477,82\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"6\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?fit=477%2C82&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=477%2C82&#038;ssl=1\" alt=\"\" class=\"wp-image-3151\" style=\"aspect-ratio:5.817991233085572;width:414px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?w=477&amp;ssl=1 477w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=300%2C52&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=18%2C3&amp;ssl=1 18w\" sizes=\"auto, (max-width: 477px) 100vw, 477px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Tras sustituir las constantes de integraci\u00f3n en las ecuaciones, obtenemos la forma final de las ecuaciones:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"752\" height=\"237\" data-attachment-id=\"3153\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/attachment\/7\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?fit=752%2C237&amp;ssl=1\" data-orig-size=\"752,237\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"7\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?fit=752%2C237&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=752%2C237&#038;ssl=1\" alt=\"\" class=\"wp-image-3153\" style=\"aspect-ratio:3.1733845169545747;width:606px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?w=752&amp;ssl=1 752w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=300%2C95&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=18%2C6&amp;ssl=1 18w\" sizes=\"auto, (max-width: 752px) 100vw, 752px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una vez que tenemos las ecuaciones en esta forma, sustituyendo n\u00fameros entre 0 y 2 m en lugar de x nos dar\u00e1 la flecha de desviaci\u00f3n y el \u00e1ngulo de desviaci\u00f3n de nuestra viga a lo largo de su longitud, y podemos dibujarlos como una gr\u00e1fica. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"759\" height=\"737\" data-attachment-id=\"3155\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/attachment\/8\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?fit=759%2C737&amp;ssl=1\" data-orig-size=\"759,737\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?fit=759%2C737&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=759%2C737&#038;ssl=1\" alt=\"desviaci\u00f3n y \u00e1ngulo de desviaci\u00f3n de un ejemplo de viga simplemente apoyada, resuelta\" class=\"wp-image-3155\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?w=759&amp;ssl=1 759w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=300%2C291&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=12%2C12&amp;ssl=1 12w\" sizes=\"auto, (max-width: 759px) 100vw, 759px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<h2 id=\"Przyk\u0142ad2\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">Ejemplo 2: Viga en voladizo - flexi\u00f3n y c\u00e1lculos<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">En el caso de <strong>soporte, c\u00e1lculos de deformaci\u00f3n<\/strong> tienen un aspecto ligeramente diferente debido a la restricci\u00f3n. W <strong>viga en voladizo<\/strong> la mayor flexi\u00f3n y el mayor \u00e1ngulo de rotaci\u00f3n se producen en el propio extremo libre.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A continuaci\u00f3n encontrar\u00e1s un ejemplo de soluci\u00f3n para calcular la flexi\u00f3n de una viga. Para las soluciones de ejemplo he utilizado <a href=\"https:\/\/solveredu.com\/es\/calculadora-de-vigas\/\" data-type=\"page\" data-id=\"166\">calculadora de haces<\/a> que te recomiendo.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">En nuestro ejemplo, hay una viga de longitud L restringida en el extremo izquierdo en el punto A y cargada con una fuerza concentrada F=5qL en el otro extremo.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"695\" height=\"666\" data-attachment-id=\"3158\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-1\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?fit=695%2C666&amp;ssl=1\" data-orig-size=\"695,666\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.1\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?fit=695%2C666&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=695%2C666&#038;ssl=1\" alt=\"longitud de la viga en voladizo L, momento flector , solveredu\" class=\"wp-image-3158\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?w=695&amp;ssl=1 695w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=300%2C287&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=13%2C12&amp;ssl=1 13w\" sizes=\"auto, (max-width: 695px) 100vw, 695px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Para calcular la flexi\u00f3n, necesitaremos el momento flector, as\u00ed que primero tenemos que resolver la viga determinando las ecuaciones de reacci\u00f3n y momento flector. M\u00e1s informaci\u00f3n en <a href=\"https:\/\/solveredu.com\/es\/post\/fuerzas-internas-en-vigas\/\" data-type=\"post\" data-id=\"899\">entrada<\/a>. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C\u00e1lculo de reacciones en soportes. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"366\" height=\"270\" data-attachment-id=\"3160\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-3-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?fit=366%2C270&amp;ssl=1\" data-orig-size=\"366,270\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?fit=366%2C270&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=366%2C270&#038;ssl=1\" alt=\"\" class=\"wp-image-3160\" style=\"aspect-ratio:1.3556545896515801;width:283px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?w=366&amp;ssl=1 366w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=300%2C221&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=16%2C12&amp;ssl=1 16w\" sizes=\"auto, (max-width: 366px) 100vw, 366px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">C\u00e1lculo del momento flector en compartimentos. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"466\" height=\"263\" data-attachment-id=\"3161\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-4-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?fit=466%2C263&amp;ssl=1\" data-orig-size=\"466,263\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.4\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?fit=466%2C263&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=466%2C263&#038;ssl=1\" alt=\"\" class=\"wp-image-3161\" style=\"aspect-ratio:1.7719089774820271;width:346px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?w=466&amp;ssl=1 466w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=300%2C169&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=18%2C10&amp;ssl=1 18w\" sizes=\"auto, (max-width: 466px) 100vw, 466px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una vez determinadas las ecuaciones del momento flector de nuestra viga de ejemplo, podemos pasar a la integraci\u00f3n y a la determinaci\u00f3n de la l\u00ednea de flexi\u00f3n. Para ello, utilizaremos la ecuaci\u00f3n del momento flector y la integraremos dos veces. La primera ecuaci\u00f3n nos da la soluci\u00f3n para el \u00e1ngulo de flexi\u00f3n y la segunda para la flexi\u00f3n. Y as\u00ed obtenemos 2 constantes de integraci\u00f3n C1 y C2.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"594\" height=\"165\" data-attachment-id=\"3162\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-5-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?fit=594%2C165&amp;ssl=1\" data-orig-size=\"594,165\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.5\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?fit=594%2C165&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=594%2C165&#038;ssl=1\" alt=\"\" class=\"wp-image-3162\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?w=594&amp;ssl=1 594w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=300%2C83&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=18%2C5&amp;ssl=1 18w\" sizes=\"auto, (max-width: 594px) 100vw, 594px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">En el siguiente paso, tenemos que calcular las constantes de integraci\u00f3n. Para este esquema es crucial que en el punto de sujeci\u00f3n tanto la desviaci\u00f3n como el \u00e1ngulo de giro sean cero. De este modo <strong>diagrama de \u00e1ngulos de rotaci\u00f3n y desviaci\u00f3n<\/strong> parte de valores cero en la pared y aumenta r\u00e1pidamente hacia el extremo de la viga.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"536\" height=\"227\" data-attachment-id=\"3163\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-6\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?fit=536%2C227&amp;ssl=1\" data-orig-size=\"536,227\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.6\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?fit=536%2C227&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=536%2C227&#038;ssl=1\" alt=\"\" class=\"wp-image-3163\" style=\"aspect-ratio:2.361489742530635;width:505px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?w=536&amp;ssl=1 536w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=300%2C127&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=18%2C8&amp;ssl=1 18w\" sizes=\"auto, (max-width: 536px) 100vw, 536px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Tras sustituir las constantes de integraci\u00f3n en las ecuaciones, obtenemos la forma final de las ecuaciones:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"582\" height=\"136\" data-attachment-id=\"3165\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-7\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?fit=582%2C136&amp;ssl=1\" data-orig-size=\"582,136\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.7\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?fit=582%2C136&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=582%2C136&#038;ssl=1\" alt=\"\" class=\"wp-image-3165\" style=\"aspect-ratio:4.279551337359793;width:533px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?w=582&amp;ssl=1 582w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=300%2C70&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=18%2C4&amp;ssl=1 18w\" sizes=\"auto, (max-width: 582px) 100vw, 582px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Una vez que tenemos las ecuaciones en esta forma, sustituyendo n\u00fameros de 0 a L en lugar de x nos dar\u00e1 la flecha de deflexi\u00f3n y el \u00e1ngulo de deflexi\u00f3n de nuestra viga a lo largo de su longitud y se puede dibujar como un gr\u00e1fico.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"641\" height=\"618\" data-attachment-id=\"3166\" data-permalink=\"https:\/\/solveredu.com\/es\/post\/obliczanie-ugiecia-belki\/2-2-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&amp;ssl=1\" data-orig-size=\"641,618\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=641%2C618&#038;ssl=1\" alt=\"\" class=\"wp-image-3166\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?w=641&amp;ssl=1 641w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=300%2C289&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=12%2C12&amp;ssl=1 12w\" sizes=\"auto, (max-width: 641px) 100vw, 641px\" \/><\/figure>\n\n\n\n<h2 id=\"Sprawd\u017a\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">5 Comprueba tus resultados: Calculadora de vigas en l\u00ednea<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Integrar el momento flector a mano es una de las habilidades m\u00e1s importantes en el estudio de la resistencia de los materiales. Es la forma en que realmente empiezas a entender c\u00f3mo funciona una viga. El problema es que, en tareas m\u00e1s complejas, es muy f\u00e1cil cometer un peque\u00f1o error: una marca por el momento, una condici\u00f3n de contorno mal escrita o un error en la integraci\u00f3n.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Por eso he creado una calculadora de deformaci\u00f3n de vigas que le permite r\u00e1pidamente <strong>verifique sus c\u00e1lculos<\/strong> - especialmente con ejemplos m\u00e1s dif\u00edciles.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Esta herramienta puede ayudarte:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Compruebe sus resultados<\/strong><br>Compara la soluci\u00f3n calculada a mano con el resultado del modelo computacional y aseg\u00farate de que tus integrales y condiciones de contorno son correctas.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Comprender mejor el comportamiento de la viga<\/strong><br>Los gr\u00e1ficos generados autom\u00e1ticamente de esfuerzos cortantes, momentos flectores y l\u00edneas de deformaci\u00f3n ayudan a ver lo que realmente ocurre en la estructura.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Enfrentarse a tareas m\u00e1s dif\u00edciles<\/strong><br>La compatibilidad con varios esquemas de carga y soporte hace que la herramienta sea ideal para ejemplos m\u00e1s dif\u00edciles de deberes o proyectos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Si quieres asegurarte de que tus c\u00e1lculos son correctos - <strong>compru\u00e9balos en segundos.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-buttons is-content-justification-center is-layout-flex wp-container-core-buttons-is-layout-69bbf988 wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-text-align-center wp-element-button\" href=\"https:\/\/solveredu.com\/es\/calculadora-de-vigas\/\" style=\"border-top-left-radius:8px;border-top-right-radius:8px;border-bottom-left-radius:8px;border-bottom-right-radius:8px\">Prueba gratis<\/a><\/div>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">No dejes que un peque\u00f1o error en la integraci\u00f3n arruine toda tu tarea. Verifica tus c\u00e1lculos y aprende resistencia de materiales mucho m\u00e1s r\u00e1pido.<\/p>","protected":false},"excerpt":{"rendered":"<p>Wyznaczanie linii ugi\u0119cia to jeden z kluczowych etap\u00f3w projektowania konstrukcji. Niezale\u017cnie od tego, czy jeste\u015b studentem przygotowuj\u0105cym si\u0119 do kolokwium z wytrzyma\u0142o\u015bci materia\u0142\u00f3w, czy in\u017cynierem weryfikuj\u0105cym sztywno\u015b\u0107 elementu, musisz wiedzie\u0107, jak \u201epracuje\u201d belka pod obci\u0105\u017ceniem. W tym artykule przejdziemy pe\u0142n\u0105 \u015bcie\u017ck\u0119: od klasycznej teorii ca\u0142kowania r\u00f3wnania r\u00f3\u017cniczkowego linii ugi\u0119cia, przez praktyczne rysowanie wykres\u00f3w k\u0105t\u00f3w obrotu, [&hellip;]<\/p>\n","protected":false},"author":255930052,"featured_media":3166,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_crdt_document":"","_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"_wpas_customize_per_network":false,"jetpack_post_was_ever_published":false},"categories":[14815,14816],"tags":[14846,14820,14845,14847],"class_list":["post-3128","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mechanika","category-wytrzymalosc-materialow","tag-belka-swobodnie-podparta","tag-rownania-rownowagi","tag-reakcje-podporowe","tag-stateczna-wyznaczalnosc"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&ssl=1","jetpack_shortlink":"https:\/\/wp.me\/pg3flK-Os","jetpack-related-posts":[],"jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/posts\/3128","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/users\/255930052"}],"replies":[{"embeddable":true,"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/comments?post=3128"}],"version-history":[{"count":31,"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/posts\/3128\/revisions"}],"predecessor-version":[{"id":3175,"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/posts\/3128\/revisions\/3175"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/media\/3166"}],"wp:attachment":[{"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/media?parent=3128"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/categories?post=3128"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/solveredu.com\/es\/wp-json\/wp\/v2\/tags?post=3128"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}