{"id":3128,"date":"2026-03-06T14:33:37","date_gmt":"2026-03-06T13:33:37","guid":{"rendered":"https:\/\/solveredu.com\/?p=3128"},"modified":"2026-03-06T14:33:42","modified_gmt":"2026-03-06T13:33:42","slug":"beam-deflection-calculation","status":"publish","type":"post","link":"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/","title":{"rendered":"Beam Deflection Calculation: From Bending Moment Integration to an Online Calculator"},"content":{"rendered":"<p class=\"has-text-align-left wp-block-paragraph\" id=\"foo\">Determining deflection lines is one of the key steps in structural design. Whether you are a student preparing for a strength of materials colloquium or an engineer verifying the stiffness of a component, you need to know how a beam \u201eworks\u201d under load.<\/p>\n\n\n\n<p class=\"has-text-align-left wp-block-paragraph\">In this article, we'll walk the full path: from classical theory <strong>Integration of the differential equation of the deflection line<\/strong>, through practical drawing of rotation angle diagrams, to examples for <strong>simply supported beam<\/strong> and <strong>bracket<\/strong><\/p>\n\n\n\n<p class=\"has-text-align-left wp-block-paragraph\" id=\"foo\">And if you value your time and want to avoid tedious hand calculations, at the end of the article you will find my <strong>proprietary beam calculator<\/strong>, which will perform these operations for you in a few seconds. Let's get started!<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong><a href=\"#Teoria-i-Metodyka\" data-type=\"internal\" data-id=\"#Teoria-i-Metodyka\">Theoretical basis: Differential equation of the deflection line<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#calkowanie\">Analytical method: Step-by-step integration<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Przyk\u0142ad1\">Example 1 : Freely supported beam<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Przyk\u0142ad2\">Example 2: cantilever beam<\/a><\/strong><\/li>\n\n\n\n<li><strong><a href=\"#Sprawd\u017a\">Quick verification: Use the online beam calculator<\/a><\/strong><\/li>\n<\/ol>\n\n\n\n<h2 id=\"Teoria-i-Metodyka\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">1 Theory and Methodology: Where does deflection come from?<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Calculation of beam deflection<\/strong> is one of the most important elements of checking the Serviceability Limit State (SGU). In order to understand this process, we need to go to the foundation of the <strong>differential equation of the beam deflection line<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The basic relationship that binds <strong>bending moment vs. deflection<\/strong>, is described by the formula:<\/p>\n\n\n\n<div class=\"wp-block-math has-medium-font-size\"><math display=\"block\"><semantics><mrow><mi>E<\/mi><mi>I<\/mi><mo>\u22c5<\/mo><msup><mi>y<\/mi><mrow><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><\/mrow><\/msup><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><mo>=<\/mo><mo form=\"prefix\" stretchy=\"false\">\u2212<\/mo><mi>M<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">EI \\dot y\u201d(x) = -M(x).<\/annotation><\/semantics><\/math><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><math data-latex=\"EI \"><semantics><mrow><mi>E<\/mi><mi>I<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">EI <\/annotation><\/semantics><\/math>- that <strong>bending stiffness of the beam<\/strong> (E - Young's modulus, I - moment of inertia of the section).<\/li>\n\n\n\n<li><math data-latex=\"y''(x)\"><semantics><mrow><msup><mi>y<\/mi><mrow><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><mo lspace=\"0em\" rspace=\"0em\" class=\"tml-prime\">\u2032<\/mo><\/mrow><\/msup><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">y\u201d(x)<\/annotation><\/semantics><\/math> - is the second derivative of deflection (curvature).<\/li>\n\n\n\n<li><math data-latex=\"M(x)\"><semantics><mrow><mi>M<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">M(x)<\/annotation><\/semantics><\/math> - is a function of the bending moment in a given section.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">We use <strong>analytical method for calculating deflections<\/strong> involves scaling this equation twice, which allows you to go from internal forces to the actual deformation of the component.<\/p>\n\n\n\n<h2 id=\"calkowanie\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">2. integrating the deflection line equation step by step<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">This part of beam deflection calculations generally causes the most problems because of the integrals, which are not liked by everyone. In the case of moment equations for beams, they are generally simple functions to integrate, so there is nothing to worry about. <strong>Integration of the deflection line equation<\/strong> We perform in two stages:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li><strong>First integration:<\/strong> Allows you to get a function of the angles of rotation of the sections <math data-latex=\"\\theta(x)\"><semantics><mrow><mi>\u03b8<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">\\theta(x)<\/annotation><\/semantics><\/math><\/li>\n\n\n\n<li><strong>Second integration:<\/strong> Allows you to determine the deflection function <math data-latex=\"y(x)\"><semantics><mrow><mi>y<\/mi><mo form=\"prefix\" stretchy=\"false\">(<\/mo><mi>x<\/mi><mo form=\"postfix\" stretchy=\"false\">)<\/mo><\/mrow><annotation encoding=\"application\/x-tex\">y(x)<\/annotation><\/semantics><\/math>, which is the deflection line being sought.<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">During the calculation, integration constants C1 and C2 appear. To determine them, we need to define the so-called. <strong>initial conditions<\/strong>, resulting from the way the beam is supported (e.g., no deflection at the support).<\/p>\n\n\n\n<h2 id=\"Przyk\u0142ad1\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">3. example 1: A simply supported beam - deflection and calculations<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">This is the most common case in the construction industry. <strong>A simply supported beam and its deflection<\/strong> with concentrated or uniform load is a classic of exam tasks.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Below you will find an example solution for calculating the deflection of the beam. For the example solutions I used <a href=\"https:\/\/solveredu.com\/en\/beam-calculator\/\" data-type=\"page\" data-id=\"166\">beam calculator<\/a> Which I recommend to you.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In our example, there is a 2m-long beam supported at two ends and loaded with a continuous load q and a concentrated force F. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"724\" height=\"668\" data-attachment-id=\"3143\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/1-5\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?fit=724%2C668&amp;ssl=1\" data-orig-size=\"724,668\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"1\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?fit=724%2C668&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=724%2C668&#038;ssl=1\" alt=\"a beam of 2m length supported at two ends and loaded with a continuous load q and a concentrated force F, solveredu\" class=\"wp-image-3143\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?w=724&amp;ssl=1 724w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=300%2C277&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/1.jpg?resize=13%2C12&amp;ssl=1 13w\" sizes=\"auto, (max-width: 724px) 100vw, 724px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">To calculate the deflection we will need the bending moment, so first we need to solve the beam by determining the reaction and bending moment equations. For more on this, see this <a href=\"https:\/\/solveredu.com\/en\/post\/internal-forces-in-beams\/\" data-type=\"post\" data-id=\"899\">entry<\/a>. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Calculation of reactions in supports. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"556\" height=\"273\" data-attachment-id=\"3144\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-5\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?fit=556%2C273&amp;ssl=1\" data-orig-size=\"556,273\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?fit=556%2C273&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=556%2C273&#038;ssl=1\" alt=\"\" class=\"wp-image-3144\" style=\"aspect-ratio:2.036689370957587;width:406px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?w=556&amp;ssl=1 556w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=300%2C147&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.jpg?resize=18%2C9&amp;ssl=1 18w\" sizes=\"auto, (max-width: 556px) 100vw, 556px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Calculation of bending moment in compartments. <\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"520\" data-attachment-id=\"3145\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/3-4\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?fit=1114%2C566&amp;ssl=1\" data-orig-size=\"1114,566\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?fit=1024%2C520&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=1024%2C520&#038;ssl=1\" alt=\"\" class=\"wp-image-3145\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=1024%2C520&amp;ssl=1 1024w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=300%2C152&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=768%2C390&amp;ssl=1 768w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?resize=18%2C9&amp;ssl=1 18w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/3.jpg?w=1114&amp;ssl=1 1114w\" sizes=\"auto, (max-width: 1000px) 100vw, 1000px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Once we have determined the equations for the bending moment for our example beam, we can move on to integration and from determining the deflection line. To do this, we use the equations for the bending moment for each compartment calculated in the previous step and integrate them twice. The first equation gives us the solution for the angle of deflection the second for the deflection. And in this way we get 4 integration constants C1, C2, C3, C4. two constants for each compartment. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"718\" height=\"259\" data-attachment-id=\"3147\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/4-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?fit=718%2C259&amp;ssl=1\" data-orig-size=\"718,259\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"4\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?fit=718%2C259&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=718%2C259&#038;ssl=1\" alt=\"calculation of beam deflection, solvered\" class=\"wp-image-3147\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?w=718&amp;ssl=1 718w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=300%2C108&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/4.jpg?resize=18%2C6&amp;ssl=1 18w\" sizes=\"auto, (max-width: 718px) 100vw, 718px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">In the next step, we need to calculate the integration constants. To do this, we will use the initial conditions.<strong> The rule is that we need as many conditions as there are integration constants<\/strong>- In our case 4. At the locations of the supports, we are sure that there will be no deflection of the beam, so y(x) at the locations of the supports is taken equal to zero. In addition, we know that at the junction of two compartments we must have continuity of deflection and deflection angle, so we have two additional equations.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"522\" height=\"193\" data-attachment-id=\"3149\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/5-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?fit=522%2C193&amp;ssl=1\" data-orig-size=\"522,193\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"5\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?fit=522%2C193&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=522%2C193&#038;ssl=1\" alt=\"\" class=\"wp-image-3149\" style=\"aspect-ratio:2.7048012306695814;width:439px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?w=522&amp;ssl=1 522w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=300%2C111&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/5.jpg?resize=18%2C7&amp;ssl=1 18w\" sizes=\"auto, (max-width: 522px) 100vw, 522px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Having the boundary conditions, we proceed to calculate the integration constants, by substituting the appropriate values into the equations. This is now pure mathematics. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The results obtained for the integration constants<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"477\" height=\"82\" data-attachment-id=\"3151\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/6-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?fit=477%2C82&amp;ssl=1\" data-orig-size=\"477,82\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"6\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?fit=477%2C82&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=477%2C82&#038;ssl=1\" alt=\"\" class=\"wp-image-3151\" style=\"aspect-ratio:5.817991233085572;width:414px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?w=477&amp;ssl=1 477w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=300%2C52&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/6.jpg?resize=18%2C3&amp;ssl=1 18w\" sizes=\"auto, (max-width: 477px) 100vw, 477px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">After substituting the integration constants into the equations, we get the final form of the equations:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"752\" height=\"237\" data-attachment-id=\"3153\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/attachment\/7\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?fit=752%2C237&amp;ssl=1\" data-orig-size=\"752,237\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"7\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?fit=752%2C237&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=752%2C237&#038;ssl=1\" alt=\"\" class=\"wp-image-3153\" style=\"aspect-ratio:3.1733845169545747;width:606px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?w=752&amp;ssl=1 752w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=300%2C95&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/7.jpg?resize=18%2C6&amp;ssl=1 18w\" sizes=\"auto, (max-width: 752px) 100vw, 752px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Once we have the equations in this form, substituting in place of x numbers in the range of 0 to 2 m, we get the deflection arrow and deflection angle of our beam along its length and can draw them in the form of a graph. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"759\" height=\"737\" data-attachment-id=\"3155\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/attachment\/8\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?fit=759%2C737&amp;ssl=1\" data-orig-size=\"759,737\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?fit=759%2C737&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=759%2C737&#038;ssl=1\" alt=\"deflection and deflection angle of an example of a simply supported beam, solvered\" class=\"wp-image-3155\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?w=759&amp;ssl=1 759w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=300%2C291&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/8.jpg?resize=12%2C12&amp;ssl=1 12w\" sizes=\"auto, (max-width: 759px) 100vw, 759px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<h2 id=\"Przyk\u0142ad2\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">4. example 2: cantilever beam - deflection and calculations<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">In the case of <strong>bracket, deflection calculations<\/strong> They look slightly different because of the restraint. W <strong>cantilever beam<\/strong> The greatest deflection and the largest angle of rotation occur at the free end itself.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Below you will find an example solution for calculating the deflection of the beam. For the example solutions I used <a href=\"https:\/\/solveredu.com\/en\/beam-calculator\/\" data-type=\"page\" data-id=\"166\">beam calculator<\/a> Which I recommend to you.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In our example, there is a beam of length L restrained on the left side at point A and loaded with a concentrated force F=5qL at the other end.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"695\" height=\"666\" data-attachment-id=\"3158\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-1\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?fit=695%2C666&amp;ssl=1\" data-orig-size=\"695,666\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.1\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?fit=695%2C666&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=695%2C666&#038;ssl=1\" alt=\"cantilever beam length L, bending moment , solveredu\" class=\"wp-image-3158\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?w=695&amp;ssl=1 695w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=300%2C287&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.1.jpg?resize=13%2C12&amp;ssl=1 13w\" sizes=\"auto, (max-width: 695px) 100vw, 695px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">To calculate the deflection we will need the bending moment, so first we need to solve the beam by determining the reaction and bending moment equations. For more on this, see this <a href=\"https:\/\/solveredu.com\/en\/post\/internal-forces-in-beams\/\" data-type=\"post\" data-id=\"899\">entry<\/a>. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Calculation of reactions in supports. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"366\" height=\"270\" data-attachment-id=\"3160\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-3-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?fit=366%2C270&amp;ssl=1\" data-orig-size=\"366,270\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?fit=366%2C270&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=366%2C270&#038;ssl=1\" alt=\"\" class=\"wp-image-3160\" style=\"aspect-ratio:1.3556545896515801;width:283px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?w=366&amp;ssl=1 366w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=300%2C221&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.3-1.jpg?resize=16%2C12&amp;ssl=1 16w\" sizes=\"auto, (max-width: 366px) 100vw, 366px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Calculation of bending moment in compartments. <\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"466\" height=\"263\" data-attachment-id=\"3161\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-4-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?fit=466%2C263&amp;ssl=1\" data-orig-size=\"466,263\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.4\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?fit=466%2C263&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=466%2C263&#038;ssl=1\" alt=\"\" class=\"wp-image-3161\" style=\"aspect-ratio:1.7719089774820271;width:346px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?w=466&amp;ssl=1 466w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=300%2C169&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.4.jpg?resize=18%2C10&amp;ssl=1 18w\" sizes=\"auto, (max-width: 466px) 100vw, 466px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Once we have determined the equations for the bending moment for our example beam, we can move on to integration and from determining the deflection line. To do this, we use the equation for the bending moment and integrate it twice. The first equation gives us the solution for the angle of deflection the second for the deflection. And in this way we get 2 integration constants C1 and C2.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"594\" height=\"165\" data-attachment-id=\"3162\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-5-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?fit=594%2C165&amp;ssl=1\" data-orig-size=\"594,165\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.5\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?fit=594%2C165&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=594%2C165&#038;ssl=1\" alt=\"\" class=\"wp-image-3162\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?w=594&amp;ssl=1 594w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=300%2C83&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.5.jpg?resize=18%2C5&amp;ssl=1 18w\" sizes=\"auto, (max-width: 594px) 100vw, 594px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">In the next step, we need to calculate the integration constants. Key to this scheme is that at the point of restraint, both the deflection and the angle of rotation are zero. With this <strong>rotation and deflection angle diagram<\/strong> starts from zero values at the wall and rises sharply toward the end of the beam.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"536\" height=\"227\" data-attachment-id=\"3163\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-6\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?fit=536%2C227&amp;ssl=1\" data-orig-size=\"536,227\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.6\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?fit=536%2C227&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=536%2C227&#038;ssl=1\" alt=\"\" class=\"wp-image-3163\" style=\"aspect-ratio:2.361489742530635;width:505px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?w=536&amp;ssl=1 536w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=300%2C127&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.6.jpg?resize=18%2C8&amp;ssl=1 18w\" sizes=\"auto, (max-width: 536px) 100vw, 536px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">After substituting the integration constants into the equations, we get the final form of the equations:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"582\" height=\"136\" data-attachment-id=\"3165\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-7\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?fit=582%2C136&amp;ssl=1\" data-orig-size=\"582,136\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.7\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?fit=582%2C136&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=582%2C136&#038;ssl=1\" alt=\"\" class=\"wp-image-3165\" style=\"aspect-ratio:4.279551337359793;width:533px;height:auto\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?w=582&amp;ssl=1 582w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=300%2C70&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.7.jpg?resize=18%2C4&amp;ssl=1 18w\" sizes=\"auto, (max-width: 582px) 100vw, 582px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Once we have the equations in this form, substituting in place of x the numbers from 0 to L will give us the deflection arrow and deflection angle of our beam along its length, and we can draw them in graph form.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"641\" height=\"618\" data-attachment-id=\"3166\" data-permalink=\"https:\/\/solveredu.com\/en\/post\/obliczanie-ugiecia-belki\/2-2-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&amp;ssl=1\" data-orig-size=\"641,618\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"2.2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=641%2C618&#038;ssl=1\" alt=\"\" class=\"wp-image-3166\" srcset=\"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?w=641&amp;ssl=1 641w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=300%2C289&amp;ssl=1 300w, https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?resize=12%2C12&amp;ssl=1 12w\" sizes=\"auto, (max-width: 641px) 100vw, 641px\" \/><\/figure>\n\n\n\n<h2 id=\"Sprawd\u017a\" class=\"wp-block-heading\" style=\"font-size:clamp(16.293px, 1.018rem + ((1vw - 3.2px) * 0.777), 25px);\">5 Check your results: Online beam calculator<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Manual integration of bending moment is one of the most important skills in studying strength of materials. It's how you really begin to understand how a beam works. The problem is that in more complex tasks, it's very easy to make a small mistake - a mark by the moment, a poorly written boundary condition or a mistake in integration.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">That's why I created a beam deflection calculator that allows you to quickly <strong>verify your calculations<\/strong> - especially with more difficult examples.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This tool can help you:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Check your results<\/strong><br>Compare the solution calculated by hand with the result from the computational model and make sure that your integrals and boundary conditions are correct.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Better understand the behavior of the beam<\/strong><br>Automatically generated plots of shear forces, bending moments and deflection lines help you see what's really going on in the structure.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Deal with more difficult tasks<\/strong><br>Support for various load and support schemes makes the tool great for more challenging examples from homework or projects.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">If you want to make sure that your calculations are correct -. <strong>check them out in seconds.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-buttons is-content-justification-center is-layout-flex wp-container-core-buttons-is-layout-69bbf988 wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-text-align-center wp-element-button\" href=\"https:\/\/solveredu.com\/en\/beam-calculator\/\" style=\"border-top-left-radius:8px;border-top-right-radius:8px;border-bottom-left-radius:8px;border-bottom-right-radius:8px\">Try for free<\/a><\/div>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Don't let one small mistake in integration ruin the whole task. Verify your calculations and learn strength of materials much faster.<\/p>","protected":false},"excerpt":{"rendered":"<p>Wyznaczanie linii ugi\u0119cia to jeden z kluczowych etap\u00f3w projektowania konstrukcji. Niezale\u017cnie od tego, czy jeste\u015b studentem przygotowuj\u0105cym si\u0119 do kolokwium z wytrzyma\u0142o\u015bci materia\u0142\u00f3w, czy in\u017cynierem weryfikuj\u0105cym sztywno\u015b\u0107 elementu, musisz wiedzie\u0107, jak \u201epracuje\u201d belka pod obci\u0105\u017ceniem. W tym artykule przejdziemy pe\u0142n\u0105 \u015bcie\u017ck\u0119: od klasycznej teorii ca\u0142kowania r\u00f3wnania r\u00f3\u017cniczkowego linii ugi\u0119cia, przez praktyczne rysowanie wykres\u00f3w k\u0105t\u00f3w obrotu, [&hellip;]<\/p>\n","protected":false},"author":255930052,"featured_media":3166,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"jetpack_post_was_ever_published":false},"categories":[14815,14816],"tags":[14846,14820,14845,14847],"class_list":["post-3128","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mechanika","category-wytrzymalosc-materialow","tag-belka-swobodnie-podparta","tag-rownania-rownowagi","tag-reakcje-podporowe","tag-stateczna-wyznaczalnosc"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2026\/03\/2.2.jpg?fit=641%2C618&ssl=1","jetpack_shortlink":"https:\/\/wp.me\/pg3flK-Os","jetpack-related-posts":[],"jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/posts\/3128","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/users\/255930052"}],"replies":[{"embeddable":true,"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/comments?post=3128"}],"version-history":[{"count":31,"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/posts\/3128\/revisions"}],"predecessor-version":[{"id":3175,"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/posts\/3128\/revisions\/3175"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/media\/3166"}],"wp:attachment":[{"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/media?parent=3128"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/categories?post=3128"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/solveredu.com\/en\/wp-json\/wp\/v2\/tags?post=3128"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}