{"id":1325,"date":"2024-09-23T14:59:12","date_gmt":"2024-09-23T12:59:12","guid":{"rendered":"https:\/\/solveredu.com\/?p=1325"},"modified":"2026-01-27T23:48:56","modified_gmt":"2026-01-27T22:48:56","slug":"beams-with-hinges-example-solutions","status":"publish","type":"post","link":"https:\/\/solveredu.com\/cs\/post\/obliczanie-belek-z-przegubem\/","title":{"rendered":"V\u00fdpo\u010det kloubov\u00fdch nosn\u00edk\u016f"},"content":{"rendered":"

V tomto z\u00e1znamu:<\/p>\n\n\n\n

    \n
  1. P\u0159\u00edklad \u0159e\u0161en\u00ed kloubov\u00e9ho nosn\u00edku.<\/a><\/li>\n\n\n\n
  2. P\u0159\u00edklad \u0159e\u0161en\u00ed pro v\u00edceramenn\u00fd nosn\u00edk.<\/a><\/li>\n<\/ol>\n\n\n\n

    V\u00fdpo\u010det kloubov\u00fdch nosn\u00edk\u016f - p\u0159\u00edklady \u00faloh<\/h1>\n\n\n\n

    N\u00ed\u017ee na obr\u00e1zku najdete nosn\u00edk, kter\u00fd budeme \u0159e\u0161it. Nosn\u00edk m\u00e1 jeden vnit\u0159n\u00ed kloub<\/strong>.<\/p>\n\n\n\n

    \"Reakce<\/figure>\n\n\n\n

    V\u00fdpo\u010det nosn\u00edk\u016f zah\u00e1j\u00edme kontrolou statick\u00e9 ur\u010ditelnosti pro nosn\u00edk, kter\u00fd vypad\u00e1 takto. V\u00edce informac\u00ed o kontrole statick\u00e9 ur\u010ditelnosti naleznete v \u010d\u00e1sti zde<\/a>.<\/p>\n\n\n\n

    N=R-J-3<\/em>=4-1-3=0
    Kde:
    N - stupe\u0148 statick\u00e9 nepr\u016fkaznosti
    R =4 - po\u010det podp\u016frn\u00fdch reakc\u00ed
    J =1 - po\u010det vnit\u0159n\u00edch spoj\u016f
    3 - po\u010det rovnov\u00e1\u017en\u00fdch rovnic. Ve statick\u00fdch syst\u00e9mech je to 3<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Proto\u017ee v bod\u011b B m\u00e1me vnit\u0159n\u00ed kloub, nahrad\u00edme p\u0159i ur\u010dov\u00e1n\u00ed stupn\u011b statick\u00e9 ur\u010ditosti za J hodnotu 1. V\u00fdsledek, kter\u00fd dostaneme, je nula, tak\u017ee nosn\u00edk je staticky ur\u010dit\u00fd. V dal\u0161\u00edm kroku vypo\u010d\u00edt\u00e1me reakce z rovnic rovnov\u00e1hy.<\/p>\n\n\n\n

    Diagram nosn\u00edku, v\u0161echny v\u00fdpo\u010dty a diagramy vnit\u0159n\u00edch sil jsou generov\u00e1ny v m\u00e9m programu. Kalkula\u010dka Nosn\u00edk\u016f<\/a>. Diagramy nosn\u00edk\u016f m\u016f\u017eete vytvo\u0159it online a z\u00edskat podrobn\u00e9 \u0159e\u0161en\u00ed pro ka\u017ed\u00fd staticky ur\u010dit\u00fd nosn\u00edk. <\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Reakce vypo\u010d\u00edt\u00e1me stejn\u00fdm zp\u016fsobem jako u p\u0159\u00edm\u00e9ho nosn\u00edku. Kv\u016fli kloubu nap\u00ed\u0161eme dal\u0161\u00ed rovnici rovnov\u00e1hy.<\/p>\n\n\n\n

    \"Reakce<\/figure>\n\n\n\n

    Sou\u010det moment\u016f kolem bodu B na prav\u00e9 stran\u011b je nulov\u00fd. Kloub n\u00e1m umo\u017e\u0148uje napsat rovnici pro ohybov\u00fd moment pouze pro jednu ze stran nosn\u00edku, pravou nebo levou. Volba je na n\u00e1s. V tomto p\u0159\u00edkladu je vhodn\u011bj\u0161\u00ed zvolit pravou stranu.<\/p>\n\n\n\n

    Po v\u00fdpo\u010dtu reakc\u00ed p\u0159ejd\u011bme k ur\u010den\u00ed t\u011bchto hodnot. vnit\u0159n\u00ed s\u00edly<\/a> v p\u0159ihr\u00e1dk\u00e1ch.<\/p>\n\n\n\n

    U kloubov\u00e9ho nosn\u00edku postupujeme \u00fapln\u011b stejn\u011b jako u p\u0159\u00edm\u00e9ho nosn\u00edku. V diskutovan\u00e9m p\u0159\u00edkladu m\u00e1me t\u0159i odd\u011blen\u00ed. Ur\u010den\u00ed smykov\u00fdch sil a ohybov\u00fdch moment\u016f najdete na obr\u00e1zku n\u00ed\u017ee.<\/p>\n\n\n\n

    \"V\u00fdsledky<\/figure>\n\n\n\n
    \"V\u00fdsledky<\/figure>\n\n\n\n
    \"V\u00fdsledky<\/figure>\n\n\n\n
    V\u0161imn\u011bte si, \u017ee ohybov\u00fd moment v kloubu v bod\u011b B je nulov\u00fd. Je to proto, \u017ee kloub z definice nep\u0159en\u00e1\u0161\u00ed ohybov\u00fd moment, tak\u017ee nulov\u00fd ohybov\u00fd moment v kloubu by m\u011bl v\u017edy vyj\u00edt v \u00faloh\u00e1ch s nosn\u00edkem s kloubem.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Po ur\u010den\u00ed smykov\u00fdch sil a ohybov\u00fdch moment\u016f v charakteristick\u00fdch bodech m\u016f\u017eeme p\u0159ej\u00edt ke kreslen\u00ed diagram\u016f.<\/p>\n\n\n\n

    \"V\u00fdsledky<\/figure>\n\n\n\n

    A t\u00edm \u0159e\u0161en\u00ed p\u0159\u00edkladu nosn\u00edku s jedn\u00edm vnit\u0159n\u00edm kloubem kon\u010d\u00ed.<\/p>\n\n\n\n

    P\u0159\u00edklad \u0159e\u0161en\u00ed v\u00edceramenn\u00e9ho nosn\u00edku<\/h2>\n\n\n\n

    Jako dal\u0161\u00ed p\u0159\u00edklad vy\u0159e\u0161\u00edme nosn\u00edk se dv\u011bma z\u00e1v\u011bsy. Postup je stejn\u00fd jako u nosn\u00edku s jedn\u00edm z\u00e1v\u011bsem. Rozd\u00edl bude v tom, kdy budeme ps\u00e1t rovnice rovnov\u00e1hy. V tomto p\u0159\u00edpad\u011b budeme m\u00edt o jednu rovnici v\u00edce.<\/p>\n\n\n\n

    \"Multibeam,<\/figure>\n\n\n\n

    Kontrola statick\u00e9 ur\u010ditelnosti takov\u00e9ho nosn\u00edku je n\u00e1sleduj\u00edc\u00ed.<\/p>\n\n\n\n

    N=R-J-3<\/em>=5-2-3=0
    Kde:
    N - stupe\u0148 statick\u00e9 nepr\u016fkaznosti
    R =5 - po\u010det podp\u016frn\u00fdch reakc\u00ed
    J =2 - po\u010det vnit\u0159n\u00edch spoj\u016f
    3 - po\u010det rovnov\u00e1\u017en\u00fdch rovnic. Ve statick\u00fdch syst\u00e9mech je to 3<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Proto\u017ee p\u0159i ur\u010dov\u00e1n\u00ed stupn\u011b statick\u00e9 determinovatelnosti m\u00e1me vnit\u0159n\u00ed kloub v bod\u011b B a D, nahrad\u00edme J \u010d\u00edslem \u201e2\u201d. V\u00fdsledek, kter\u00fd dostaneme, je nula, tak\u017ee nosn\u00edk je staticky ur\u010diteln\u00fd. V dal\u0161\u00edm kroku vypo\u010d\u00edt\u00e1me reakce z rovnic rovnov\u00e1hy.<\/p>\n\n\n\n

    \"Reakce<\/figure>\n\n\n\n

    Reakce vypo\u010d\u00edt\u00e1me stejn\u00fdm zp\u016fsobem jako u p\u0159\u00edm\u00e9ho nosn\u00edku. Kv\u016fli kloub\u016fm nap\u00ed\u0161eme dv\u011b dal\u0161\u00ed rovnice rovnov\u00e1hy.<\/p>\n\n\n\n

    Stejn\u011b jako u nosn\u00edku s jedn\u00edm kloubem m\u016f\u017eeme zvolit stranu, vzhledem k n\u00ed\u017e ur\u010d\u00edme ohybov\u00fd moment v kloubu. V tomto p\u0159\u00edkladu je v\u00fdhodn\u011bj\u0161\u00ed lev\u00e1 strana. Jak pro kloub B, tak pro kloub v bod\u011b D.<\/p>\n\n\n\n

    Po v\u00fdpo\u010dtu reakc\u00ed p\u0159ejd\u011bme k ur\u010den\u00ed t\u011bchto hodnot. vnit\u0159n\u00ed s\u00edly<\/a> v p\u0159ihr\u00e1dk\u00e1ch.<\/p>\n\n\n\n

    U kloubov\u00e9ho nosn\u00edku postupujeme \u00fapln\u011b stejn\u011b jako u p\u0159\u00edm\u00e9ho nosn\u00edku. V tomto p\u0159\u00edkladu m\u00e1me a\u017e \u0161est odd\u011blen\u00ed. Smykov\u00e9 s\u00edly a ohybov\u00e9 momenty najdete na obr\u00e1zku n\u00ed\u017ee.<\/p>\n\n\n\n

    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    \"\"<\/figure>\n\n\n\n
    V\u0161imn\u011bte si, \u017ee ohybov\u00fd moment v kloubu v bod\u011b B a v kloubu D je nulov\u00fd. Je to proto, \u017ee kloub z definice nep\u0159en\u00e1\u0161\u00ed ohybov\u00fd moment, tak\u017ee v \u00faloh\u00e1ch nosn\u00edku s kloubem by m\u011bl v\u017edy vych\u00e1zet nulov\u00fd ohybov\u00fd moment v kloubu.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

    Nakonec stanov\u00edme pr\u016fb\u011bhy smykov\u00fdch sil a ohybov\u00fdch moment\u016f ve form\u011b diagram\u016f.<\/p>\n\n\n\n

    \"Kloubov\u00fd<\/figure>\n\n\n\n

    A t\u00edm kon\u010d\u00ed \u010dl\u00e1nek \u201eV\u00fdpo\u010det nosn\u00edk\u016f s kloubem\u201d. D\u011bkujeme, \u017ee jste do\u010detli a\u017e do konce.<\/p>","protected":false},"excerpt":{"rendered":"

    W tym wpisie: Obliczanie Belek z przegubem – Przyk\u0142adowe rozwi\u0105zania zada\u0144 Poni\u017cej na rys. Znajdziesz belk\u0119 kt\u00f3ra rozwi\u0105\u017cemy. Belka posiada jeden przegub wewn\u0119trzny. Obliczanie belek rozpoczynamy od sprawdzenia statycznej wyznaczalno\u015bci dla belki wygl\u0105da nast\u0119puj\u0105co. Wi\u0119cej o sprawdzeniu statycznej wyznaczalno\u015bci znajdziesz tutaj. N=R-J-3=4-1-3=0gdzie:N \u2013 stopie\u0144 statycznej niewyznaczalno\u015b\u0107R =4 \u2013 liczba reakcji podporowychJ =1 \u2013 liczba przegub\u00f3w […]<\/p>\n","protected":false},"author":255930052,"featured_media":1355,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"jetpack_post_was_ever_published":false},"categories":[14815,14816],"tags":[14855,14857,14856,14859,14858],"class_list":["post-1325","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mechanika","category-wytrzymalosc-materialow","tag-belka-z-przegubem","tag-momenty-gnace","tag-przegub-wewnetrzny","tag-wykres-sil-tnacych","tag-wykresy-momentu-gnacego"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"https:\/\/i0.wp.com\/solveredu.com\/wp-content\/uploads\/2024\/09\/wykresy_2-1.png?fit=1033%2C886&ssl=1","jetpack_shortlink":"https:\/\/wp.me\/pg3flK-ln","jetpack-related-posts":[],"jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/posts\/1325","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/users\/255930052"}],"replies":[{"embeddable":true,"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/comments?post=1325"}],"version-history":[{"count":24,"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/posts\/1325\/revisions"}],"predecessor-version":[{"id":3079,"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/posts\/1325\/revisions\/3079"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/media\/1355"}],"wp:attachment":[{"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/media?parent=1325"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/categories?post=1325"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/solveredu.com\/cs\/wp-json\/wp\/v2\/tags?post=1325"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}